Boolean rings and Boolean algebras

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SUMMARY

This discussion clarifies the relationship between Boolean rings and Boolean algebras, specifically how a Boolean algebra is derived from a Boolean ring using the operations defined as xANDy=xy, xORy=x+y+xy, and xNOT=1+x. The participant raises a critical point regarding the involution property of xNOT, arguing that (xNOT)NOT does not equal x, leading to the conclusion that xNOT should be defined as -x to satisfy this property. The discussion also touches on the idempotent nature of Boolean rings, where x+x=0, reinforcing the unique characteristics of Boolean algebra.

PREREQUISITES
  • Understanding of Boolean rings and their operations
  • Familiarity with Boolean algebra concepts
  • Knowledge of idempotent rings and their properties
  • Basic grasp of algebraic structures in mathematics
NEXT STEPS
  • Study the properties of Boolean rings in detail
  • Explore the implications of involution in algebraic structures
  • Investigate idempotent rings and their applications
  • Learn about the relationship between Boolean algebras and other algebraic systems
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Mathematicians, computer scientists, and students studying algebraic structures, particularly those interested in the foundations of Boolean algebra and its applications in logic and computation.

quasar987
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My professor wrote that we get a Boolean algebra from a Boolean ring (R,+,-,.,0,1) by setting xANDy=xy, xORy=x+y+xy and xNOT=1+x.

But it seems to me that xNOT is not an involution. I.e., (xNOT)NOT = 1+(1+x), which is not x.

(xNOT=-x would do the trick though)
 
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It seems to me that

1+(1+x) = x

For several reasons. What else would it be equal to? Doesn't 1 + 1 = 0?
 
I forgot about that. In an idempotent ring, x+x=0.
 

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