How Do You Calculate Hydrostatic Pressure in a Spherical Water Tank?

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To calculate the maximum volume of water in a spherical tank with an 8.6-meter diameter, first determine the hydrostatic pressure at the bottom using the formula P = ρgh, where ρ is the water density (approximately 1000 kg/m³), g is gravitational acceleration (9.81 m/s²), and h is the height of the water column. Given that the maximum allowable hydrostatic pressure is 50 kilopascals, solve for the height of the water column, which is approximately 5.1 meters. Using the height, calculate the volume of the sphere with the formula V = (4/3)πr³, where r is the radius (4.3 meters). The final volume, rounded to the nearest 10 liters, will provide the answer for the maximum water capacity of the tank.
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I have this homework problem and I can't figure it out:

Suppose you have a perfectly spherical water tank with an inside diameter of 8.6 metres. If the drain at the bottom of the tank can't handle a hydrostatic pressure of more than 50 kilopascals, what is the maximum volume of water, in litres, that can be contained in the tank? Assume that gravitational acceleration is exactly 9.81 m/s2. Please round to the nearest 10 litre increment, and please submit only a number for your answer. (For example, if you calculate the answer to be 16277 litres, submit 16280 as your answer)

All I can figure out is the volume of the sphere =/

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