Dipole (electrical) and Electric Field Concept

AI Thread Summary
Dipoles consist of two point charges of equal magnitude but opposite signs separated by a distance. The electric field direction at a point along the dipole axis aligns with the axis itself, which can be the z-axis if defined that way. This can be understood through the principle of superposition, where the fields from each charge are added vectorially. If the dipole axis is oriented along the z-axis, the electric field at points along this axis will also point in the z direction. Clarification of the textbook's explanation helped resolve the initial confusion regarding the electric field's direction.
wk1989
Messages
32
Reaction score
1
Hi all, I'm kind of confused right now about some concepts.

- Dipoles are essentially point charges of the same magnitude but different signs that are a certain distance away from each other, right?

-In my textbook, they were calculating a charged particle that is on the dipole axis. They got an a E that is in the direction of z (as opposed to x/y). Why is the direction of the electric field at the point P (on the dipole axis) z? The charges of the dipole and the charge at P are all on x, y plane, unless I misunderstood something.

-However, in earlier examples with charges on the same plane with other charges, the E they got was restricted in the x,y plane.

Why is this so? Am I missing something?

Thanks in advance!
 
Physics news on Phys.org
If the dipole axis is in the direction of z, then the field at a point on the axis will also point along the z direction. You can understand this using the principle of superposition. Work out what the field due to each charge will be and add them (vector addition).
 
The dipole axis is a line going through both charges. If that axis is the z-axis, then the field at some point along the z-axis will be parallel to the z-axis. On the other hand, the field at some point on the x-y plane that bisects the dipole (assume the dipole is at z = 0) will also be parallel to the z-axis.

(dx beat me too it!)
 
Never mind, I misunderstood what the textbook was saying, thanks for the input though.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
I was thinking using 2 purple mattress samples, and taping them together, I do want other ideas though, the main guidelines are; Must have a volume LESS than 1600 cubic centimeters, and CAN'T exceed 25 cm in ANY direction. Must be LESS than 1 kg. NO parachutes. NO glue or Tape can touch the egg. MUST be able to take egg out in less than 1 minute. Grade A large eggs will be used.
Back
Top