Why Are {111} Planes the Primary Slip Systems in Face Centered Cubic Metals?

AI Thread Summary
The discussion focuses on the slip systems of face-centered cubic (FCC) metals, specifically the {111}<110> slip system, which consists of 12 slip systems. The {111} family includes various crystallographic planes such as (111), (-111), (1-11), and (11-1). The inquiry centers on why only specific planes are considered slip planes for FCC metals, despite the existence of other planes. It is noted that while slip can occur on other planes, dislocation movement is facilitated on close-packed planes, making {111}<110> the preferred slip system for FCC crystals. In contrast, body-centered cubic (BCC) metals utilize a different slip system, {110}<111>, due to the absence of a perfectly close-packed plane in BCC structures.
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Hello,

Recently,I study about the slip systems of metals which regarding to the material science subject.
For face centered cubic(FCC),it slip system is {111}<110>.Hence the number of slip systems is 12.The{111}is the family for (111), (-111), (1-11), (11-1),(sorry!-1 means a bar line on top of 1).
From what I study about{111}which is the family,it not just containing those few crystallographic planes that I listed out on top,but why other planes are not consider as slip planes for FCC?

Thanks very much, I appreciate any insight.
 
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Slip can occur on other planes, but it's especially easy for a dislocation to move in the close-packed direction along a close-packed plane. For fcc crystals, this means {111}<110>. For bcc, it's {110}<111> (the close-packed direction on the closest-packed plane--there is no perfectly close-packed plane in bcc).
 
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