Solving Fractional Exponent with Elementary Laplace

2RIP
Messages
62
Reaction score
0
Hi

Homework Statement


L[f] = (s)^(1/2)

The Attempt at a Solution


Is there actually an elementary laplace transform that can compute this? I tried using derivative to solve for it, but i'll always be stuck with a fractional exponent.

Thanks
 
Physics news on Phys.org
The best thing I could think of is using the convolution rule, i.e. (F(s)G(s) = f(t)*g(t)) where * is convolution. Let F(s)=G(s)=s^(1/2), then F(s)G(s) = s. Can you do the laplace transform of s?
 
Oh, our class hasn't got to that section yet. Maybe I'll be able to solve it tomorrow then. Thanks.
 
I think i might have just thought of something. Would it work if i first took the derivative. Then used the gamma function to compute the inverse laplace transform?
 
The gamma function isn't in a form that is immediately obvious to me to see how it relates to what you have to evaluate.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top