Calculate Escape Velocity to Leave Solar System

AI Thread Summary
To calculate the escape velocity required for a spacecraft to leave the solar system, one must consider both Earth's and the Sun's gravitational influences. The correct approach involves using the formula for escape velocity, Vesc = √(2GM/r), but it is essential not to simply add the distances from Earth and the Sun. Instead, the potential energies from both celestial bodies should be combined, leading to the equation V² = Ve² + Vs², where Ve and Vs are the escape velocities from Earth and the Sun, respectively. This method accounts for the gravitational pull of both bodies and allows for an accurate calculation of the necessary escape velocity. Understanding these principles is crucial for spacecraft trajectory planning.
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Homework Statement


when a spacecraft escapes from the earth, it still has to escape from the sun, in order to leave the solar system. at what velocity should a spacecraft be launched if it is 6.4x10^6 meters from Earth's centre and 1.5x10^11 meteres from the sun (M=2x10^30 kg) if it is to escape the solar system.

G=6.672x10^-11

Homework Equations


i think Vesc.=(2GM)/r


The Attempt at a Solution


i was thinking to plug in the sun's mass for M, but for r, i was thinking to put in 6.4x10^6 + 1.5x10^11 for r, am i even using the right formula? I'm pretty sure that i am, i just am confused over the use of 2 distances
 
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You certainly wouldn't add the radii together.

But you can add the potential energies together such that the potential energy that you need to overcome with respect to Earth and the potential energy you need to overcome with respect to the Sun both can be figured and added which becomes the root sum of the squares of the individual escape velocities.

PE = GMe/Re + GMs/Rs = 1/2v2 - which is the KE needed.

(The m's of the space shot cancel out.)

In case you don't recognize that what you have is:

V2 = Ve2 +Vs2
 
thank you so much
 
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