What is the ball's maximum acceleration?

AI Thread Summary
The discussion centers on calculating the maximum acceleration of a 160 g ball attached to a spring with a spring constant of 2.8 N/m. The initial calculation yields an acceleration of 78.75 cm/s² using the formula a = kx/m. However, participants note that the spring constant's units (N/m) and the velocity's units (cm/s) must be consistent. To determine the maximum acceleration, it's suggested to find the maximum displacement (x_max) using the given velocity. The conversation emphasizes the need to correctly apply the principles of oscillation and unit conversion for accurate results.
lijoeman
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Homework Statement


A 160 g ball attached to a spring with spring constant 2.8 N/m oscillates horizontally on a frictionless table. Its velocity is 20 cm/s when x_0 = 4.5 cm.

a_max = _______ cm/s^2


2. The attempt at a solution

Using F = ma and F = kx
kx = ma
a = kx/m

Substituting the appropriate values

a = (2.8)(4.5)/(.16) = 78.75 cm/s^2

Am I missing something here?
 
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lijoeman said:

Homework Statement


A 160 g ball attached to a spring with spring constant 2.8 N/m oscillates horizontally on a frictionless table. Its velocity is 20 cm/s when x_0 = 4.5 cm.

a_max = _______ cm/s^2


2. The attempt at a solution

Using F = ma and F = kx
kx = ma
a = kx/m

Substituting the appropriate values

a = (2.8)(4.5)/(.16) = 78.75 cm/s^2

Am I missing something here?

check your units. your spring constant is in N/m, while you're speed is in cm/s
 
lijoeman said:
Using F = ma and F = kx
kx = ma
a = kx/m
That gives you the acceleration at some particular value of x. It will only be a_max when x = x_max.

How can you find the maximum value of x? Hint: Make use of the speed that was given.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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