Chromatic number of the n-cube

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The chromatic number of the n-cube is established as 2, indicating that it is a bipartite graph. For both the square and the 3-cube, this holds true, supported by empirical evidence. The vertices of the n-cube can be labeled using vectors in {0, 1}^n, allowing for a clear partition based on the parity of the number of 1's. This bipartite nature confirms that only two colors are needed for proper vertex coloring. Thus, the discussion concludes that the chromatic number of the n-cube is definitively 2.
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What is the chromatic number of the n-cube? As a graph, I mean. For the square and 3-cube, for example, it's 2.
 
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Empirical evidence suggests it's just 2.
 
The n-cube is bipartite, so its chromatic number is 2. If we label the vertices canonically with vectors in \{0, 1\}^n, then we can partition the vertices into those with an even number of 1's and those with an odd number of 1's.
 
Oh ya, thanks.
 
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