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Simple Precalculus: Average rate of change 
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#1
Jun1109, 10:10 PM

P: 81

1. The problem statement, all variables and given/known data
Find the average rate of change: g(x)=1/x; x = 1, x = a 2. Relevant equations (f(b)f(a))/(ba) = Average rate of change 3. The attempt at a solution I've spent far too much time on this problem, but I know I'm making a stupid error and I just can't pin it down. So far, the steps I'm pretty confident about: g(1) = 1/1 = 1 g(a) = 1/a Average rate of change = ((1/a)1)/(a1) According to the book the answer is (1/a)... but I'm just not seeing it. 


#2
Jun1109, 10:16 PM

HW Helper
P: 6,205

1/a1 = (1a)/a



#3
Jun1109, 11:46 PM

P: 81

Yea, got it now. It was just as ridiculous an oversight as I had originally thought. I kept getting to the point in the problem where I had (1a)/(a(a1)) and going, "Oh, I can't divide those binomials!" Factor out a 1 from the numerator, cancel out the resulting binomial with the denominator and there's the answer... staring me right in the face. I'm rather embarrassed that I had so much trouble with such a simple problem, and that I forgot such a basic rule. Thanks for the help.



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