Relating pressure and height in a container


by Linus Pauling
Tags: container, height, pressure, relating
Linus Pauling
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#1
Nov14-09, 12:45 PM
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1. A container of uniform cross-sectional area A is filled with liquid of uniform density rho. Consider a thin horizontal layer of liquid (thickness dy) at a height y as measured from the bottom of the container. Let the pressure exerted upward on the bottom of the layer be p and the pressure exerted downward on the top be p+dp. Assume throughout the problem that the system is in equilibrium (the container has not been recently shaken or moved, etc.).

Since the liquid is in equilibrium, the net force on the thin layer of liquid is zero. Complete the force equation for the sum of the vertical forces acting on the liquid layer described in the problem introduction.




2. 0 = sum of forces in y direction



3. Ok, I know that F_up = pA
F_down = A(p + dp)
weight of the thin layer = pAg dy

So I did:

pA - A(p+dp) - pAgdy = -Ap(d + dyg) = 0

And it's telling me that the answer does not depend on d.
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Doc Al
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Nov14-09, 01:00 PM
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Quote Quote by Linus Pauling View Post
3. Ok, I know that F_up = pA
F_down = A(p + dp)
OK.
weight of the thin layer = pAg dy
Do you mean: rho*Ag dy ?

When you set up your equation, you won't have a 'd' by itself.
Linus Pauling
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Nov14-09, 01:14 PM
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Quote Quote by Doc Al View Post
OK.

Do you mean: rho*Ag dy ?

When you set up your equation, you won't have a 'd' by itself.

My bad, yes it's rho*Ag dy

Thus:

F = F_up - F_down - rho*Agdy
= pA - A(p + dp) - g*rho*A dy
= -dp - g*rho*A dy

which is incorrect

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Nov14-09, 01:59 PM
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Relating pressure and height in a container


Quote Quote by Linus Pauling View Post
F = F_up - F_down - rho*Agdy
= pA - A(p + dp) - g*rho*A dy
= -dp - g*rho*A dy
Redo the last step--you dropped an A.


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