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Finding the value for rejection region using some kind of table... 
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#1
Dec1409, 02:18 PM

P: 20

I'm lost no how to find the cutoff rejection region and which table to use?
This is an example, Data n 34 Xbar 10.3 s 3.1 98% Confidence Interval for µ is 10.3 ± 2.33 x 0.5316 = (9.0632 , 11.5368) Hypothesis H0: µ ≤ 9 H1: µ > 9 Tests Zstat = 1.3 = 2.4452 Statistic 0.5316 Significance Level = 0.01 Rejection Region = Tail = RIGHT Cutt Off = Zalpha = 2.326 Decision = Reject H0 pvalue = 0.0072 I understand how they reject H0, but I am lost how they got 2.326. I think it's in the Ztable but I'm not sure, can someone explain to me clearly. It would also help if you can tell me how to find 0.0072 for the pvalue. 


#2
Dec1509, 07:42 AM

HW Helper
P: 1,361

I'm not sure how your Z table is set up  whether it gives only tail areas or cumulative probabilities.
If it gives tail areas (areas to the right of specific Zvalues, do this: look through the AREAS for 0.01  the associated Zvalue will be 2.326 If your Z table gives cumulative probabilities (areas of the form P(Z <=z)), look for the area that is closest to 0.99 (this is 1  0.01)  again, the Zvalue should be 2.236. Some tables only give the area between 0 and specified values of Z. If this is the case, look through the areas for the value closest to 0.49  again, you should find Z = 2.236. 


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