|Register to reply||
Finding the value for rejection region using some kind of table...
|Share this thread:|
Dec14-09, 02:18 PM
I'm lost no how to find the cutoff rejection region and which table to use?
This is an example,
98% Confidence Interval for µ is
10.3 ± 2.33 x 0.5316
= (9.0632 , 11.5368)
H0: µ ≤ 9
H1: µ > 9
Tests Z-stat = 1.3 = 2.4452
Significance Level = 0.01
Rejection Region =
Tail = RIGHT
Cutt -Off = Z-alpha = 2.326
Decision = Reject H0
p-value = 0.0072
I understand how they reject H0, but I am lost how they got 2.326. I think it's in the Z-table but I'm not sure, can someone explain to me clearly. It would also help if you can tell me how to find 0.0072 for the p-value.
Dec15-09, 07:42 AM
I'm not sure how your Z table is set up - whether it gives only tail areas or cumulative probabilities.
If it gives tail areas (areas to the right of specific Z-values, do this: look through the AREAS for 0.01 - the associated Z-value will be 2.326
If your Z- table gives cumulative probabilities (areas of the form P(Z <=z)), look for the area that is closest to 0.99 (this is 1 - 0.01) - again, the Z-value should be 2.236.
Some tables only give the area between 0 and specified values of Z. If this is the case, look through the areas for the value closest to 0.49 - again, you should find Z = 2.236.
|Register to reply|
|Finding area of shaded region||Calculus & Beyond Homework||13|
|Finding Area of Region||Calculus & Beyond Homework||6|
|Finding the centroid of the triangular region||Calculus & Beyond Homework||7|
|Pre-Calculus - Regarding finding the area of a certain region||Introductory Physics Homework||4|
|Finding the area of the region||Introductory Physics Homework||4|