Solving the 411nm Wavelength Emission from Hydrogen

AI Thread Summary
The discussion revolves around identifying the transition responsible for the 411 nm wavelength emission from hydrogen. The relevant formula, R = (1/n^2 - 1/k^2), is used to calculate the wavelength based on different energy level transitions. Participants express uncertainty about the correct options, eliminating choices a, b, and e, and focusing on c and d. A suggestion is made to plug in the values for k and n from the remaining options into the formula to determine which produces the correct wavelength. The conversation emphasizes the need for clarity in applying the Rydberg formula to solve the problem.
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Homework Statement



Light of wavelength 411 nm is emitted from a hydrogen discharge. What transition produces this emission?

a. k = 5 to n =1
b. k = 4.5 to n = 2
c. k = 2 to n = 6
d. k = 2 to n = 3
e. k = 6 to n = 2

Homework Equations



R = (1/n^2 - 1/k^2)

The Attempt at a Solution



I'm not really sure how to solve it. But I'm sure its not a, b, or e. Because n to be bigger then k to make it positive. THat left me with c and d. Someone please hint me how to do this.
 
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Just plug in the choices for k and n pairs in the formula and see which one gives you the right wavelength.
 
totally confused. >< can someone explain it to me.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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