Box hanging from a rope, need to know the force.

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A 23 kg box hanging from a rope requires calculations for tension under various conditions. When at rest, the tension is 225.4 N due to gravitational force. For constant velocity (5.0 m/s), the tension remains the same at 225.4 N, indicating equilibrium. In scenarios where the box accelerates upwards or decelerates, the tension must account for the additional forces from acceleration. Understanding Newton's second law is crucial for solving these problems accurately.
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A 23 kg box hangs from a rope. What is the tension in the rope if the following are true?

a)The box is at rest?
b)The box moves up at a steady 5.0 m/s?
c)The box has Vy = 5.0 m/s and is speeding up at 5.0 m/s^2?
d)The box has Vy = 5.0 m/s and is slowing down at 5.0 m/s^2


I have gotten a) = 225.4N. Because acceleration is 0. I do not know how to go about solving the other three parts though.

I know the force of gravity is acting on the box in addition to the tension force.

For b):
Since velocity is constant, I would think that the forces would be in equilibrium. But apparently I am wrong. I really have no idea how to solve this.

Any help at all would be appreciated.
 
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I figured it out. Now I feel stupid. Since acceleration is 0 (constant velocity), there would be no change in the force. So for b) the answer would still be 225.4N.
 
This is good, now try 'c' and 'd' using Newtons 2nd law. Welcome to PF!
 
Thanks.

Yeah, sorry I never replied back last night. But I did get the right answers. As soon as I figured out what was going on, everything just clicked.

What I was doing wrong for c and d was that I wasn't accounting for the the change in force. I just found the force with those particular amounts of acceleration.
 
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