
#1
Mar2210, 03:02 PM

P: 157

Greetings,
I am trying to figure out how to modify the equations for a trefoil knot to make it toroidal. A trefoil knot is: x = (2 + cos 3t)cos 2t y = (2 + cos 3t)sin 2t z = sin 3t A torus is: x(u, v) = (R + r cos v) cos u y(u, v) = (R + r cos v) sin u z(u,v) = r sin v where u, v are in the interval [0, 2π), R is the distance from the center of the tube to the center of the torus, r is the radius of the tube. Thanks 



#2
Apr910, 05:58 AM

P: 336

A comparison of the equations suggests that we set R=2, r=1 & (u,v) =(2t,3t).



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