- #1
Schu
- 12
- 0
Particulars:
ball has a radius of 2.5 cm a mass of .125 and is rolling across a table with a speed of .547 m/s, this table is 1.04 m off the ground. It rolls to the edge and down a ramp How fast will it be rolling across the floor?
First I found the Gravitational Potential Energy: Ep=mgh
Initial of 1.2753 FInal = 0
THen the Linear Kinetic ENergy : 1/2 mv^2
Initial .0187005625 FInal .0625v^2
Elastic Potential Energy: .5k(delta)x^2
0 0
Rotational Kinetic Energy: 1/5mv^2
initial .007480225 FInal .025v^2
Now I need to bring them all togther and solve the final velocity.
Is the Sum of the inital energy's = to the SUM of the final energy's?
If that's true then 1.30148075 = .0875v^2
so v = 3.85 m/s
Is that at all right??
ball has a radius of 2.5 cm a mass of .125 and is rolling across a table with a speed of .547 m/s, this table is 1.04 m off the ground. It rolls to the edge and down a ramp How fast will it be rolling across the floor?
First I found the Gravitational Potential Energy: Ep=mgh
Initial of 1.2753 FInal = 0
THen the Linear Kinetic ENergy : 1/2 mv^2
Initial .0187005625 FInal .0625v^2
Elastic Potential Energy: .5k(delta)x^2
0 0
Rotational Kinetic Energy: 1/5mv^2
initial .007480225 FInal .025v^2
Now I need to bring them all togther and solve the final velocity.
Is the Sum of the inital energy's = to the SUM of the final energy's?
If that's true then 1.30148075 = .0875v^2
so v = 3.85 m/s
Is that at all right??