
#1
Apr2010, 11:32 AM

P: 62

Hi,
I have a gaussian of the form [tex]exp[\frac{\pi*x^{2}}{A^2}][/tex]. I know that the FWHM=0.939A, but I cannot prove it. I Let [tex]exp[\frac{\pi*x^{2}}{A^2}=0.5[/tex] (i.e. the half maximum part) taking natural logs I get rid of the exponential, but then which bit represents the full width? 



#2
Apr2010, 04:23 PM

Sci Advisor
P: 5,937

Write x = kA and compute k=(ln(.5)/π)^{1/2}
Your Gaussian looks funny. 


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