How do you evaluate e^{\sqrt{i}} algebraically?

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Discussion Overview

The discussion focuses on the algebraic evaluation of the expression e^{\sqrt{i}}, exploring different methods and interpretations related to complex numbers and their polar forms.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant suggests using the polar form of i, expressed as exp(i*pi/2), to find sqrt(i) and then evaluate exp(a+bi).
  • Another participant confirms that taking i = e^{i \frac {pi}{2}} leads to sqrt(i) = e^{i \frac {pi}{4}}, proposing to use trigonometric form for evaluation.
  • A later reply introduces the idea of considering the second root, exp[i(pi/4 + pi)], indicating the presence of multiple values in the evaluation.
  • One participant acknowledges the complexity of dealing with multiple values in the complex plane.

Areas of Agreement / Disagreement

Participants express differing views on the evaluation process, particularly regarding the consideration of multiple roots, indicating that the discussion remains unresolved.

Contextual Notes

Participants note the importance of recognizing multiple values in complex evaluations, which may depend on the chosen branch of the logarithm.

Who May Find This Useful

This discussion may be of interest to those studying complex analysis, particularly in understanding the evaluation of expressions involving complex exponentials and roots.

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How do you evaluate this expression algebraically.

[tex] e^{\sqrt{i}} [/tex]
 
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Since i=exp(i*pi/2), you can determine easily sqrt(i) in polar form, then in rectangular form: a+bi. Then you can evaluate exp(a+bi).
 
If you take [itex]i = e^{i \frac {pi}{2}}[/itex] then [itex]\sqrt i = e^{i \frac {pi}{4}}[/itex]. Just write it in trig form and put into your expression.
 
easy peasy. thanks
 
Not quite. Don't forget the second root exp[i(pi/4 + pi)].
 
Ahh yes, those pesky multiple values. That complex plane will eventually bend to my will.
 

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