| New Reply |
Surjective functions |
Share Thread | Thread Tools |
| Mar10-11, 02:12 AM | #1 |
|
|
Surjective functions
1. The problem statement, all variables and given/known data
i) Show explicitly that any non-injective function with a right inverse has another right inverse ii) Give an example of a function which has (at least) two distinct left inverses 2. Relevant equations i) I don't believe there are any. ii) " 3. The attempt at a solution i) Since it says "explicitly" I doubt that my attempt would count as a solution even if it were correct, but here it is; Since the function is non-injective and has a right inverse, it must therefore be surjective as it cannot be bijective, and in order for this function to be surjective it must have at least one more right inverse. I also tried showing first that f(x) = x^3 - x is non-injective and then showing that the values x = -1,0,1 map to f(x) = 0 that I would be showing this is true but I am not sure if it is correct. ii) For this I am really not sure if there is an easier way to do it apart from trial and error but I understand the theory behind it. Thanks in advance, SD123 |
| Mar10-11, 04:25 AM | #2 |
|
|
Try something as simple as this: f:{a, b, c}--> {x, y} defined by f(a)= x,f(b)= x, f(c)= y. g:{x, y}-->{a, b, c}, defined by g(x)= a, g(y)= c is a right inverse.
Think about that example to prove (i). However, note that an example is NOT a general proof. |
| New Reply |
| Thread Tools | |
Similar Threads for: Surjective functions
|
||||
| Thread | Forum | Replies | ||
| i need to prove that the following is not surjective. how do i do | Set Theory, Logic, Probability, Statistics | 2 | ||
| ratio of functions, surjective (analysis course) | Calculus & Beyond Homework | 3 | ||
| quick question about surjective functions | Calculus & Beyond Homework | 1 | ||
| Surjective | Calculus & Beyond Homework | 1 | ||
| Cartesian product & Surjective functions | Calculus & Beyond Homework | 8 | ||