Solving Pascals Principle for Hydraulic Jack - F2 = 10.8N

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The discussion revolves around solving a problem related to Pascal's Principle in a hydraulic jack scenario. The user applies the equations of pressure, P1 = P2 and P = F/A, to find the load supported by the jack. They express uncertainty about calculating P1, given their lack of familiarity with hydraulic jacks. After some calculations, they arrive at a load F2 of 10.8 N. The user seeks confirmation on their interpretation and solution approach.
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Homework Statement


A hydraulic jack has the dimensions as shown in the figure to the left. A force F of 120 N is exerted on the handle of the jack. What load, F2, is being supported by the jack?


Homework Equations


P1=P2
P=F/A


The Attempt at a Solution



I know that P1=P2
And P2 = F2*0.025^2*pi
What I am having trouble with is P1. I never seen a hydraulic jack before so I don't quite understand how that pressure works there. My guess here would be 120*A1=F2*0.025^2*pi
Solving for F2 gives 10.8N. Did i interpret the question correctly?
 
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Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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