|Oct30-04, 03:19 PM||#1|
Q is at one point
R is the radius of this cylinder, it's height is 2h
the cylinder is without the bases.
how can i calculate the electric flow through it?
the final answer is Q/[epsilon0*sqrt(1+R^2/h^2)]
|Oct30-04, 03:30 PM||#2|
Why don't you try calculating the flux through the flat top and bottom of the cylinder? Then you could subtract it from the total flux given by Gauss' Law.
|Oct30-04, 03:38 PM||#3|
we take ball with radius sqrt(R^2+h^2) and look on the rounded bases: the area of this ball inside the cylinder.
flow through bases / flow through all ball = bases area / all ball area
gaus: all ball flow is Q/epsilon0
all ball area is 4pi(R^2+h^2)
base area = circumference of projection of the base on y=2h * height of base
2 bases area = base area * 2 = 4pi*R[sqrt(R^2+h^2)-h]
flow through bases=bases area*flow through all ball / all ball area=
= 4pi(R^2+h^2)Q/(epsilon0 4pi*R[sqrt(R^2+h^2)-h])=
now that's not like that right answer, coz we can assign r=1 h=1
my answer qives 2/(sqrt(2)-1) * Q/epsilon0 = 2(1+sqrt(2)) * Q/epsilon0
right answer gives 1/sqrt(2) * Q/epsilon0
|Oct30-04, 03:39 PM||#4|
S r^2/(r^2+h^2)^(3/2) dr
or something like that
|Similar Threads for: electric flow|
|period of an electric dipole rotating in an external electric field||Introductory Physics Homework||2|
|Transition from pipe flow to open channel flow||Mechanical Engineering||6|
|Can an inviscid flow rotational? Potential Flow?||Mechanical Engineering||2|
|Temp flow and electrical flow||Classical Physics||5|
|Electric Flow||Classical Physics||36|