Interference in Thin Films, figuring out the phases

AI Thread Summary
The discussion focuses on understanding phase changes in thin film interference, particularly when determining conditions for constructive interference (maxima). The problem involves light incident on a thin layer of material with specific refractive indices, and the goal is to find the thickness for the third least maximum. A key point raised is the need to add an additional λ/2 due to phase inversion upon reflection, leading to the equation 2L=(m+1/2)λ/n2. Participants emphasize the significance of using 2m+1 for odd numbers in this context, as it relates to achieving the necessary phase conditions for maxima. The conversation highlights the importance of visualizing wave propagation to understand the interference patterns.
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Homework Statement


I don't have a question on a specific problem, I am more caught up in the determination of the phases- I'll give a general problem to use as an example:

In Fig. 35-41, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. The waves of rays r1 and r2 interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). We are given:

n1=1.32
n2=1.75
n3=1.39
we want to find a max
for the 3rd least thickness of L (in nm)
λ=382nm (in air)

Figure:
nt0043-y.gif


rays are tilted for clarity

Homework Equations


Since we want a maximum, the general equation for a maximum would be:
2L=(m+1/2)λ/n2


The Attempt at a Solution



in the case of this problem, we add an additional λ/2 for the incidence of r1 on n2.
so my real question is this-

why is it that you multiply m by 2 to end up with 2m+1 in this case? when do you just use (m+1)λ vs (2m+1/2)λ


I've been reading and researching for hours now, so any help would truly be appreciated.
 
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High-speed to slow speed you get a phase inversion.
http://www.kettering.edu/physics/drussell/Demos/reflect/reflect.html
... it has neat animations of the effect for string, you have to scroll down for the general.

That 2m+1 gives you an odd number - do you see why an odd number is needed?

The trick is to try drawing a wave as it propagates through the film. What happens if it's an even number?
 
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