Why electric potential of arc treated like point charge

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SUMMARY

The electric potential (V) of an arc of uniform charge can be expressed as V = kQ/R, where k is Coulomb's constant, Q is the total charge, and R is the distance from the arc to the point of interest. This treatment of the arc as a point charge is valid because electric potential is a scalar quantity, allowing contributions from different charge elements to be summed directly. The concept parallels that of a conducting sphere, where charge distribution is uniform, even at the center. The integral approach to deriving the potential from point charges confirms this equivalence.

PREREQUISITES
  • Understanding of electric potential and its formula (V = kQ/R)
  • Familiarity with scalar and vector quantities in physics
  • Basic knowledge of charge distribution in conductors
  • Ability to perform integrals in the context of physics
NEXT STEPS
  • Study the concept of electric potential energy and its relation to electric potential
  • Learn about the properties of electric fields and how they differ from electric potential
  • Explore the derivation of electric potential for different charge distributions
  • Investigate the behavior of electric potential in conducting spheres and their applications
USEFUL FOR

Students in introductory physics courses, educators teaching electric potential concepts, and anyone interested in understanding the relationship between charge distributions and electric potential.

lonewolf219
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Homework Statement



Give an expression to find V of Arc of uniform charge (at the center, or origin)

Homework Equations



V=kQ/R


The Attempt at a Solution



the solution is kQ/R. I'm wondering why an arc can be treated like a point charge...
Is this reason partly connected to a conducting sphere, and the fact is has an equal charge distribution everywhere, even at its hollow center? Likewise, would a uniform arc also be seen as a hollow conducting sphere?
 
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hi lonewolf219! :smile:

electric potential is a scalar, and so we add the contributions (from different parts) as scalars (ie ordinary numbers) …

this works for any shape :wink:

(unlike electric field, which is a vector, and so we add the contributions as vectors)
 
Thanks Tiny-Tim...

Just starting the second semester of introductory physics. A little confusing with electric force, electric field, electric potential and electric potential energy...

As you pointed out, scalars versus vectors. But I guess there is little connection between an arc and a conducting sphere...
 
lonewolf219 said:

Homework Statement



Give an expression to find V of Arc of uniform charge (at the center, or origin)

the solution is kQ/R. I'm wondering why an arc can be treated like a point charge...

You can consider the arc as a lot of equal point charges arranged in arc from. A line element dL has a charge dQ, and contributes to the potential by dV= kdQ/R at the centre. The contributions of the charges add up: so the total potential at the centre is the integral of these contributions.

V=\int{\frac{kdQ}{R}}.

k/R is constant, it can be factored out from the integral, so V=\frac{k}{R}\int{dQ}=\frac{kQ}{R}.

ehild
 

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hi lonewolf219! :smile:

(just got up :zzz: …)
lonewolf219 said:
A little confusing with electric force, electric field, electric potential and electric potential energy...

electric force is a force (as in "F = ma")

electric field is electric force per charge

electric potential energy is what it says, the PE of the electric field

electric potential is electric potential energy per charge

(just as gravitational potential is gravitational potential energy per mass: PE/m = mgh/m = gh, or = -mMG/mr = -MG/r)
 
Thanks guys!

People like you are the reason physics forums is so awesome...
 

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