Calculating Forces & Friction on a Block Resting on an Incline

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SUMMARY

The discussion focuses on calculating the forces acting on a 5 kg block resting on a 30-degree incline with a static friction coefficient of 0.2. The equation used to analyze the forces is ma = Fapp - (m)mg - mgsin30, where Fapp represents the applied force. The participants clarify the need to determine the required horizontal force to initiate sliding both up and down the incline. Key considerations include the direction of friction and the acceleration of the block.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Knowledge of static friction and its coefficient
  • Basic trigonometry for resolving forces on an incline
  • Familiarity with free body diagrams
NEXT STEPS
  • Calculate the net force acting on the block using F = ma
  • Explore the effects of changing the angle of incline on friction
  • Learn about kinetic friction and its differences from static friction
  • Investigate the role of normal force in inclined plane problems
USEFUL FOR

Students studying physics, engineers working on mechanics, and anyone interested in understanding forces and friction in inclined plane scenarios.

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A 5 kg block rests on a 30degree incline
the coefficient of static friction is between the block and incline is 0.2
how large a horizontal force must push on the block if the block is to be on the verge of sliding a)up the incline and b) down the incline

So far I have ma=Fapp-(m)mg-mgsin30
where (m) is miu or friction co-efficient

ive been working on this for a long time but not sure how to get the answers
any help will be much appreciated!
 
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Welcome to PF;
Would you be able to do this if the block were not on an incline?

So far you have ##ma=F_{app}-\mu_kmg - mg\sin{\theta}## (resist the urge to put the numbers in so soon).

Is this for pushing the block up or down the slope?
Which direction does friction act?

According to the description: what is the acceleration?
 

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