Sum of work = Work done by net force

by Bipolarity
Tags: force, work
Bipolarity is offline
Jan23-13, 03:35 PM
P: 783
Suppose you have many forces acting on an object, and the object moves in space in some time interval. Each force has done some work on the object.
Suppose you took all these values for work, added them up, (they are all scalars). You'd obtain a scalar equal to the net work done on the object. Forces that are acute to the object's displacement at some instant tend to increase this net work, whereas forces obtuse tend to decrease this net work. Forces orthogonal to the displacement at an instant do not affect the net work done on the object.

On the other hand, suppose you took each force acting on the object and summed them all up vectorially, obtaining the net force on the object. You then treat this force as a single force, and find the work done by this one force. Would this work be the same as that obtained in the previous answer?

I've been thinking about this, and am pretty sure the answer is yes, but can anyone confirm this with a yes or a no? I don't want any explanations I'll figure those out myself.

Also, in the work-kinetic energy theorem, the change in KE of the object is equal to the net-work done on the system right? The same net work calculated above in two different ways, right?

Just need a confirmation. Thank you all.

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dydxforsn is offline
Jan23-13, 03:45 PM
P: 111
The answer is yes, you're correct (about everything).

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