Register to reply 
Can someone clarify and shed some light about these two statements 
Share this thread: 
#1
Feb2113, 06:10 PM

P: 2

If every dynamic variable in a physics problem is a measurement derived from a particular coordinate system how do you explain the contradiction both statements 1 and 2 imply if they are both simultaneously true:
1. According to relativity (relative velocity etc.) every measurement of position, distance, displacement, velocity and acceleration is dependent on the particular coordinate system used to make the measurements and by that logic every observer should get a different measurement based on the particular coordinate system used (i.e. placement of origin and orientation of axes) 2. According to transformation laws and tensor analysis vectors and scalars are covariant or form invariant and therefore measurements do not depend on the particular coordinate system used and by that logic every observer should get the same measurement regardless of their particular frame of reference Unless I have grossly misunderstood physics and how we acquire information about the world (which is more than likely the case) there seems to be a major contradiction here. Correct me if I am wrong please because I do not see a way out of this conundrum!!! 


#2
Feb2113, 07:17 PM

Sci Advisor
HW Helper
Thanks
PF Gold
P: 5,062

What 1 refers to are the components of vectors and tensors as reckoned from various coordinate systems. As you know, the vectors themselves can be expressed as the sum of their components times the unit vectors in the coordinate directions. If you change frame of reference (coordinate system), you change the unit vectors, and, that causes the vector components to change. But the sum of the components times the unit vectors remains the same.
Item 2 refers to the vectors themselves (not their components). Of course, the vectors themselves do not change when you change frame of reference. 


#3
Feb2113, 07:30 PM

P: 2

Thanks Chestmiller!! I have taken quite a few physics courses and the all the information starts to blur after awhile if I dont keep the concepts straight lol!! I guess I need to practice more problems!! But you hit the nail on the head by clarifying the distinctions between the actual vector and the vector representation in a particular coordinate system. I guess as I was learning physics that concept was not made clear enough to me or I didnt give it the attention it deserved.
Thanks a million jrist29 


#4
Feb2113, 07:52 PM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 39,348

Can someone clarify and shed some light about these two statements
As a very very simple example, If I set up a Cartesian coordinate system in a plane, the vector from the origin, (0, 0), to the point (1, 1) is, of course, [itex]\vec{i}+ \vec{j}[/tex]. If I rotate that coordinate system so that my new xaxis was pointing along the line y= x (in the original coordinate system) then that [b]same[b] vector would be represented by [itex]\sqrt{2}\vec{i'}[/itex] where, now, [itex]\vec{i'}[/itex] is the unit vector along the new xaxis. The components have changed, but it is still the same vector. (And, in either coordinate system, it length is "invariant".)



Register to reply 
Related Discussions  
First and second derivatives. Please shed some light!  Calculus & Beyond Homework  12  
Can physics shed light on the nature of human consciousness ?  General Physics  8  
Any employers\employees here willing to shed some light on BCIT's reputation?  Career Guidance  4  
Can anybody shed some light on antilock braking systems?  Mechanical Engineering  5 