Why in smithchart 360 degree corresponds to half the wavelength

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In a Smith chart, 360 degrees corresponds to one full wavelength (λ), but a half wavelength (λ/2) represents a significant change in the reflection coefficient. A short circuit on a transmission line has a reflection coefficient of -1, plotted on the left side of the Smith chart. Lengthening the transmission line by 1/4 wavelength transforms the reflection coefficient to +1, resembling an open circuit, and moves the point to the right side of the chart. This movement illustrates that extending the line by 1/4 wavelength effectively shifts the point halfway around the Smith chart. Understanding this relationship is crucial for accurate impedance matching in RF applications.
dexterdev
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Hi,
Actually wavelength λ corresponds to 360 degrees , right? then why λ/2...
 
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Don't expect Smith chart to work like an Argand diagram.

Consider a short circuit on an electrically short transmission line. This will have reflection coefficient of -1, which will be plotted on the far left side of Smith chart. If I lengthen transmission line by 1/4 wavelength in front of short circuit, it will have a reflection coefficient of +1 (i.e. it will look like an open circuit), which will be plotted on the far right hand side of Smith chart. Extending transmission line 1/4 wavelength moved us halfway around Smith chart.
 

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