How Is Force Calculated When Wind Hits a Wall?

AI Thread Summary
The discussion focuses on calculating the force exerted by wind on a wall, given a wind speed of 33 m/s and air density of 1.2 kg/m^3. The wall's area is 12 m^2, and the air's speed is reduced to zero upon impact. Participants emphasize that this is a rate-of-change-of-momentum problem, requiring the calculation of mass striking the wall per second. Understanding the relationship between mass, velocity, and force is crucial for solving the problem. The conversation highlights the need for clarity on how to approach the calculation of the force.
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1. A strong wind of speed 33 m s^–1 blows against a wall. The density of the air is 1.2 kg m^–3. The wall has an area of 12 m^2 at right angles to the wind velocity. The air has its speed reduced to zero when it hits the wall.
What is the approximate force exerted by the air on the wall?



2. ρ= m/v. F= m/a



3. I have no idea how I would do this.
 
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Welcome to Physics Forums. This is a rate-of-change-of-momentum problem. Do you know how to calculate the rate at which mass strikes the wall (kg/sec)?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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