Find Volume of Metal Object: 860-785 N, 9.8 m/s^2

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The volume of the metal object can be determined using Archimedes' principle and the readings from a spring scale. The scale shows 860 N in air and 785 N when submerged, indicating a buoyant force of 75 N. This buoyant force equals the weight of the water displaced, allowing the use of the formula Fb = ρVg. By substituting the values, the volume is calculated to be 0.00765 m^3. Thus, the volume of the metal object is 0.00765 m^3.
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A metal object is suspended from a spring scale. The scale reads 860 N when the object is suspended in air, and 785 N when the object is completely submerged in water.
The acceleration due to gravity is 9.8 m/s^2.
Find the volume of the object. Answer in m^3.
 
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To find the volume of the metal object, we can use the principle of buoyancy. The difference in the scale readings (860 N - 785 N = 75 N) represents the buoyant force acting on the object when it is submerged in water. This buoyant force is equal to the weight of the water displaced by the object.

We can use the formula Fb = ρVg, where Fb is the buoyant force, ρ is the density of water (1000 kg/m^3), V is the volume of the object, and g is the acceleration due to gravity (9.8 m/s^2).

Substituting the given values, we get 75 N = (1000 kg/m^3) V (9.8 m/s^2).

Solving for V, we get V = 0.00765 m^3.

Therefore, the volume of the metal object is 0.00765 m^3.
 
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