Solve Gold Density Problem: Area & Length of Gold Leaf & Fiber

  • Thread starter Thread starter JudyyNunez
  • Start date Start date
  • Tags Tags
    Density Gold
AI Thread Summary
The discussion revolves around calculating the area of a gold leaf and the length of a cylindrical fiber made from gold, given its density of 19.32 g/cm3. For part (a), the area of the gold leaf was calculated to be approximately 0.01356 m², but there was confusion regarding the units and whether to account for both sides of the leaf. In part (b), participants pointed out that the formula used may have been incorrect, as it suggested that area times length equals area, which is not valid. Clarifications were made about the need to consider the leaf's two surfaces and the shape of the fiber for accurate calculations. Overall, the thread emphasizes the importance of proper unit usage and understanding the geometry involved in the problem.
JudyyNunez
Messages
3
Reaction score
0
1. Problem: Gold, which has a density of 19.32 g/cm3, is the most ductile metal and can be pressed into a thin leaf or drawn out into a long fiber. (a) If a sample of gold with a mass of 2.274 g, is pressed into a leaf of 8.678 μm thickness, what is the area (in m2) of the leaf? (b) If, instead, the gold is drawn out into a cylindrical fiber of radius 2.200 μm, what is the length (in m) of the fiber?


2. Homework Equations : a=pi x r^2 and (a)(l)= part a



3. The Attempt at a Solution : part a= 0.01356, and I tried plugging it into the equation (1.521x10^-11 m^2)(l)=0.01356

If anyone could find the error in part B! Please Help
 
Physics news on Phys.org
Units? Showing your work?
 
JudyyNunez said:
2. Homework Equations : a=pi x r^2 and (a)(l)= part a

The "(a)(l)= part a" looks wrong. The answer to part a is an area. You can't say "area times length = area".

3. The Attempt at a Solution : part a= 0.01356

That looks right (except you forgot the units).

I don't understand what you did for part (b).
 
what is the area (in m2) of the leaf?
Don't forget that the leaf has two sides, so there are two surface areas. This could be a trick question! :smile:

So state your answer as ... m2 per side for each of 2 sides.

If you knew the shape, you could also work out the area of its other very narrow side/s. :wink:
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
I was thinking using 2 purple mattress samples, and taping them together, I do want other ideas though, the main guidelines are; Must have a volume LESS than 1600 cubic centimeters, and CAN'T exceed 25 cm in ANY direction. Must be LESS than 1 kg. NO parachutes. NO glue or Tape can touch the egg. MUST be able to take egg out in less than 1 minute. Grade A large eggs will be used.
Back
Top