Calculating Balloon Volume Change with Altitude

Click For Summary
SUMMARY

The discussion focuses on calculating the volume change of a helium balloon with altitude, establishing that the volume at altitude y is given by V = V0(T1/T0)e^(+cy), where c = pg/P0 = 1.25 x 10^4 m^-1. The buoyant force remains constant regardless of altitude due to the balloon's skin maintaining helium pressure at 1.05 times the outside pressure. This relationship ensures that changes in air density and pressure do not affect the buoyant force, which is determined by the weight of the displaced air.

PREREQUISITES
  • Understanding of gas laws, specifically the ideal gas law.
  • Familiarity with buoyancy principles and Archimedes' principle.
  • Knowledge of exponential functions and their application in physics.
  • Basic concepts of atmospheric pressure changes with altitude.
NEXT STEPS
  • Study the ideal gas law and its implications for volume and pressure changes.
  • Explore Archimedes' principle in detail to understand buoyant forces.
  • Learn about atmospheric pressure variations with altitude and their effects on gas behavior.
  • Investigate the effects of temperature on gas density and volume in different conditions.
USEFUL FOR

Students and professionals in physics, aerospace engineering, and environmental science who are interested in fluid dynamics and gas behavior in varying atmospheric conditions.

physicsss
Messages
319
Reaction score
0
A helium balloon has volume V0 and temperature T0 at sea level where the pressure is P0 and the air density is p. The balloon is allowed to float up in air to altitude y where the temperature is T1.

a) Show that the colume occupised by the balloon is then V = V0(T1/T0)e^(+cy) where c = pg/P0 = 1.25 X 10^4 m^-1.

b) Show that the buoyant force does not depend on altitude y. Assume that the skin of the balloon maintains the helium pressure at a constant factor of 1.05 times greater than the outside pressure. [Hint] Assume that the pressure change with altitude is P = (P0)e^(+cy).

I was able to use the hint to do a), but I'm confused by b). Why does the book say to assume he skin of the balloon maintains the helium pressure at a constant factor of 1.05 times greater than the outside pressure?
 
Physics news on Phys.org
How does this relate to the buoyant force? a) The volume occupied by the balloon is related to the temperature, pressure and density of the air. The equation for the volume change due to a change in temperature is given by V = V0(T1/T0). The equation for the volume change due to a change in pressure is given by V = V0e^(-cy), where c = pg/P0. Combining these two equations gives us the total volume change due to both pressure and temperature changes: V = V0(T1/T0)e^(-cy). b) The buoyant force is equal to the weight of the displaced air, which is equal to the mass of the displaced air times the gravitational acceleration. The mass of the displaced air is equal to the volume of the balloon times the density of the air. The density of the air is related to the pressure by the equation p = P/RT, where R is the gas constant and T is the temperature. Thus, the buoyant force can be written as Fb = Vpg/RT. Since the pressure changes with altitude (P = P0e^(+cy)), the density of the air (p = P/RT) also changes with altitude. However, if the skin of the balloon maintains the helium pressure at a constant factor of 1.05 times greater than the outside pressure, then the helium pressure inside the balloon will remain constant, thus eliminating the effect of pressure change on the buoyant force. Therefore, the buoyant force does not depend on altitude y.
 

Similar threads

Replies
5
Views
2K
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
5K
Replies
4
Views
5K
  • · Replies 8 ·
Replies
8
Views
12K
Replies
8
Views
3K
Replies
17
Views
4K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 3 ·
Replies
3
Views
8K
  • · Replies 2 ·
Replies
2
Views
10K