Calculating Force: Understanding the 1.5m Distance in Baseball Pitching Protest

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The discussion centers on calculating the force exerted by a baseball pitcher when throwing a ball straight up at 20 m/s, with a focus on the significance of the 1.5 m distance over which the force is applied. Participants explore the relationship between work, force, and distance, noting that work is calculated as force multiplied by distance. The equation W = Ek is referenced, connecting kinetic energy to the force applied over the distance. Additionally, the relationship between force, mass, and acceleration is highlighted, emphasizing the importance of considering the distance when calculating the force exerted. Understanding these concepts is crucial for accurately determining the force involved in the pitching scenario.
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Ok, i just need to verify what this question means:

A baseball pitcher throws a ball straight up into the air at a speed of 20 m/s as a protest against the umpire's calls. In the process, he moves his hand through a distance of 1.5 m. If the ball has a mass of 0.15 kg, find the force he exerts on the ball to give it this upward speed. Note that the force of gravity is acting against the motion of the ball.


Ok, so i just have a question on what the significance of the "1.5 m " distance.
 
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HINT: Work = Force X distance
 
I see what is going on... W= Ek so, F*s = ((m*v*v)/2) . The speed is related to the Force and the distance the force was applied over.

I new that F= m*a. so speed is related to force over time. I never really considered the distance that a force is applied over.

If Hitokiri is still visiting this forum It would be interesting to know if Tides hint was of help.
 
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