MHB A bag contains x beads. Calculate the value of x.

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The problem involves calculating the total number of beads, x, in a bag containing 6 red beads and x-6 blue beads, given that the probability of drawing two beads of the same color is 9/17. The probabilities for drawing two red beads and two blue beads are calculated separately, leading to the equation 30/(x(x-1)) + ((x-6)(x-7))/(x(x-1)) = (x^2 - 13x + 72)/(x^2 - x). Setting this equal to 9/17 allows for solving for x. By cross-multiplying and simplifying, the value of x can be determined. The final solution reveals the total number of beads in the bag.
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A bag contains x beads. 6 of the beads are red and the rest are blue. Ravish is going to take at random 2 beads from the bag. The probability that the 2 beads will be of the same colour is $9 /17$
Using algebra calculate the value of x. ( show sworking if possible)
 
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There are 6 red beads and x- 6 blue beads. The probability the first bead taken is red is 6/x. In that case there are 5 red beads and x- 6 blue beads left for a total of x-1 beads. The probability the second bead is also red is 5/(x- 1). The probability the two beads are both red is (6/x)(5/(x- 1))= 30/(x(x- 1)).

There are 6 red beads and x- 6 blue beads. The probability the first bead taken is blue is (x- 6)/x. In that case there are 6 red beads and x- 7 blue beads left for a total of x- 1 beads. The probability the second bead is also blue is (x- 7)/(x- 1). The probability the to beads are both blue is ((x- 6)/x)((x- 7)/(x- 1))= (x- 6)(x-7)/(x(x- 1).

The probability the two beads are the same color is 30/(x(x-1)+ ((x- 6)(x- 7)/(x(x-1))= (x^2- 13x+ 72)/(x^2- x).

Set that equal to 9/17 and solve for x.
 
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