- #1
AlphaA
- 9
- 0
If an object say a rocket is thrown up in the sky with an additional acceleration say ' x ' , then why do we add the value of acceleration due to gravity i.e 9.8 m/s^2 to the acceleration ' x' in order to find the total acceleration...
Since vector of acceleration due to gravity is directed downwards...so we consider it - 9.8 m/s^2 . So in accordance to this, if we find total acceleration then we should subtract 9.8 m/s^2 from 'x ' m/s^2 because...firstly, gravity is -9.8 m/s^2 and secondly, acceleration due to gravity will constantly decrease if the rocket or object will continue going up int he sky with that X acceleration. So why should 9.8 m/s^2 be added to X m/s^2 and not subtracted ?
Since vector of acceleration due to gravity is directed downwards...so we consider it - 9.8 m/s^2 . So in accordance to this, if we find total acceleration then we should subtract 9.8 m/s^2 from 'x ' m/s^2 because...firstly, gravity is -9.8 m/s^2 and secondly, acceleration due to gravity will constantly decrease if the rocket or object will continue going up int he sky with that X acceleration. So why should 9.8 m/s^2 be added to X m/s^2 and not subtracted ?