Applied Maxima and Minima Problem

In summary, the conversation discusses finding the total cost function for a monopolist's product, given the demand equation and average-cost equation. The steps to finding the net profit are also outlined, with the suggestion to use completing the square to find the maximum value.
  • #1
jennifer361
1
0

Homework Statement


Problem goes like this:
For a monopolist's product, the demand equation is: p=156-2q
_
and the average-cost is c(ave)=120+112/q


Homework Equations


We need to find the total cost function in terms of c=


The Attempt at a Solution



I can't seem to figure out how to change the average cost of cost...or maybe it's simple and I'm completely missing it...any help would be greatly appreciated!
 
Physics news on Phys.org
  • #2
I'm going to assume that p is the "demand"- the number of items purchased- at price c. (In the future it would be helpful to say things like that explicetely.) Then the revenue is pq= (156-2q)q= 156q- 2q2. The average cost of each item 120- 112/q so the cost of q items is (120- 112/q)q= 120q- 112. (I have no idea what "average cost of cost" means!).

Finally, the net profit is the revenue minus the cost: 156q- 2q2- (120 q- 112)= 112+ 36q- 2q2. You should be able to find the maximum value of that by completing the square.
 
  • #3


I can understand your struggle with this problem. It seems like you are trying to find the total cost function in terms of c, which can be a bit challenging. However, let's break down the problem and see if we can find a solution.

First, let's define some terms. The demand equation, p=156-2q, represents the relationship between the price (p) and quantity (q) demanded by consumers. This equation is often referred to as the demand curve. On the other hand, the average-cost function, c(ave)=120+112/q, represents the relationship between the average cost (c) and quantity (q) produced by the monopolist.

Now, to find the total cost function, we need to understand that it is the sum of all costs incurred by the monopolist to produce a given quantity of the product. This includes both fixed costs (costs that do not change with the level of production) and variable costs (costs that vary with the level of production). In this case, the average-cost function represents the variable costs, while the fixed costs can be calculated by subtracting the variable costs from the total cost at a given quantity.

To find the total cost function in terms of c, we can use the following equation:

C(q) = c(ave) * q + F(q)

Where C(q) represents the total cost function, c(ave) represents the average-cost function, q represents the quantity produced, and F(q) represents the fixed costs.

In this case, we can substitute the average-cost function, c(ave)=120+112/q, into the equation and solve for F(q) to find the fixed costs:

C(q) = (120+112/q) * q + F(q)

C(q) = 120q + 112 + F(q)

F(q) = C(q) - 120q - 112

Now we have the fixed costs in terms of the total cost function. We can substitute this into the equation to find the total cost function in terms of c:

C(q) = c(ave) * q + (C(q) - 120q - 112)

C(q) = (120+112/q) * q + (C(q) - 120q - 112)

C(q) = 120q + 112 + C(q) - 120q - 112

C(q) = C
 

Related to Applied Maxima and Minima Problem

What is the definition of "Applied Maxima and Minima Problem"?

Applied Maxima and Minima Problem is a mathematical concept that deals with finding the maximum or minimum values of a function within a given range or constraint. It is commonly used in optimization problems in various fields such as engineering, economics, and physics.

How do you solve Applied Maxima and Minima Problems?

To solve Applied Maxima and Minima Problems, you first need to identify the function and the constraints. Then, use calculus techniques such as differentiation and critical point analysis to find the maximum or minimum values. Finally, check the endpoints and compare the values to determine the global maximum or minimum.

What are the real-life applications of Applied Maxima and Minima Problems?

Applied Maxima and Minima Problems have various real-life applications, including determining the optimal production level in a factory, maximizing profits in a business, and minimizing costs in logistics. It is also used in designing structures and systems that can withstand maximum or minimum forces.

What are the differences between local and global maxima and minima?

Local maxima and minima refer to the highest and lowest points of a function within a specific interval, while global maxima and minima are the highest and lowest points of a function within its entire domain. In other words, local maxima and minima are relative, while global maxima and minima are absolute.

How does the use of constraints affect the solutions to Applied Maxima and Minima Problems?

The use of constraints in Applied Maxima and Minima Problems limits the possible solutions and can affect the location of the maximum or minimum point. It is essential to consider the constraints when solving these problems to ensure that the solution is feasible and within the given constraints.

Similar threads

  • Quantum Physics
Replies
1
Views
904
  • Calculus and Beyond Homework Help
Replies
2
Views
1K
  • Calculus and Beyond Homework Help
Replies
16
Views
2K
  • Calculus and Beyond Homework Help
Replies
1
Views
1K
  • Precalculus Mathematics Homework Help
Replies
4
Views
4K
  • Calculus and Beyond Homework Help
Replies
2
Views
2K
  • Calculus and Beyond Homework Help
Replies
3
Views
2K
  • Calculus and Beyond Homework Help
Replies
3
Views
6K
Replies
19
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
2K
Back
Top