Calculating Force - Basketball player landing from a jump

AI Thread Summary
To calculate the force acting on a basketball player landing from a jump, the relevant equation is the force due to gravity, given by F = m * g. For a player with a mass of 112 kg, this results in a force of 1098 N, as g is approximately 9.8 m/s². The height of the jump, 0.92 m, is not necessary for this calculation and is considered a distraction. The force of gravity remains constant regardless of the jump height. Thus, the correct approach is to focus solely on the player's mass and gravitational acceleration.
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Homework Statement


Ok, relatively simple question here, but I have a newb doubt...

"A basketball player with a mass of 112kg can jump 0.92 m into the air during a slam dunk competition. Calculate the force that pulls the player back towards the floor."

Homework Equations


## \vec f = m \vec g##

The Attempt at a Solution


Is the 0.92 m height a red herring distraction?

If so it's just a straightforward 112 kg x 9.8 m/s^2 = 1098 N answer.

Am I correct to ignore the 0.92 m height?

Apologies in advance for such a basic question.
 
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It is absolutely a red herring. The force of gravity on the player close to the surface of the Earth is always his mass multiplied by g.
 
Thank you very much for your patient reply.
 
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