- #1
Roul
- 7
- 0
In the attached picture, can I say that there is a lift force in the Y-direction, and a drag force too in the same Y-direction?
FL proportional to V_fx2 ?
FD proportional to V_py2 ?
Is this equation of motion for the Y-direction correct here: ma = − mg − FD + V(rho)g + FL
The lift force is because of the horizontal flow which is in fact lifting the particle (lets assume there is some small velocity gradient around the particle, as the particle bottom experiences zero flow velocity and particle top experiences the flow velocity), and the drag force is due to the resistance to the particle's upward motion. Is this correct to say?
Please assume that the picture is correct, and such an observation was made.
Edit: Just added the image.
https://imgur.com/x099TgP
https://imgur.com/x099TgP
https://imgur.com/x099TgP
FL proportional to V_fx2 ?
FD proportional to V_py2 ?
Is this equation of motion for the Y-direction correct here: ma = − mg − FD + V(rho)g + FL
The lift force is because of the horizontal flow which is in fact lifting the particle (lets assume there is some small velocity gradient around the particle, as the particle bottom experiences zero flow velocity and particle top experiences the flow velocity), and the drag force is due to the resistance to the particle's upward motion. Is this correct to say?
Please assume that the picture is correct, and such an observation was made.
Edit: Just added the image.
https://imgur.com/x099TgP
https://imgur.com/x099TgP
https://imgur.com/x099TgP