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Homework Statement
The metabolism of glucose, C6H12O6, yields Co2(g) and H2O(l) as products. Heat released in the process is converted to useful work with about 70% efficiency.
Calculate the mass of glucose metabolized by a 59.0-kg person in climbing a mountain with an elevation gain of 1550m . Assume that the work performed in the climb is about four times that required to simply lift 59.0 kg by 1550m .
Homework Equations
(enthalpy of formation of C6H12O6(s) is -1273.3 kJ/mol.)
The Attempt at a Solution
Im so confused with this question and i do not even know where to start...Any help will be appreciated...