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Another
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problem in this book : classical mechanics goldstein
Why can we cancel the derivative of dt from these equations?
e.g.
##\frac{d(x)}{dt} + \frac{b sin\theta}{2} \frac{d(\theta)}{dt} = asin\theta \frac{d(\phi)}{dt}##
## x +\frac{b \theta sin\theta}{2} = a \phi sin\theta ##
because I think
##\frac{d(x)}{dt} + \frac{b sin\theta}{2} \frac{d(\theta)}{dt} = asin\theta \frac{d(\phi)}{dt}##
##\frac{d}{dt}(x - (b/2) cos\theta) = asin\theta \frac{d(\phi)}{dt}## due to ##sin\theta ## dependent on t. we can't cancel dt
Or it is just only divider. So We can cancel
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