- #1
lowellite
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So I know these equations
1/f = 1/p + 1/i
m = -i/p
f: focal length
p: object distance from mirror
i: image distance from mirror
m: magnification
Let's say that I have an object in front of a concave or convex mirror with the same |f|. p is much larger than the radius of curvature. Based on the equations above, |m|<1. Also, |m| should be nearly same for both mirrors. Does this mean that the images produced by the two mirrors would appear to be about the same size?
Also, if I replace the concave or convex mirror with a plane mirror (while keeping p the same), |m| would be 1 for the image. Does this mean that the image produced by the plane mirror would appear to be larger than the image produced by the concave/convex mirrors?
(I tried to check this using a spoon, but the spoons I have are not very reflective...)
1/f = 1/p + 1/i
m = -i/p
f: focal length
p: object distance from mirror
i: image distance from mirror
m: magnification
Let's say that I have an object in front of a concave or convex mirror with the same |f|. p is much larger than the radius of curvature. Based on the equations above, |m|<1. Also, |m| should be nearly same for both mirrors. Does this mean that the images produced by the two mirrors would appear to be about the same size?
Also, if I replace the concave or convex mirror with a plane mirror (while keeping p the same), |m| would be 1 for the image. Does this mean that the image produced by the plane mirror would appear to be larger than the image produced by the concave/convex mirrors?
(I tried to check this using a spoon, but the spoons I have are not very reflective...)