Confused about proof of "sin(θ + Φ) = cosθsinΦ + sinθcosΦ"

In summary, the proof uses a diagram to show that sin(θ+Φ) = cosθsinΦ + sinθcosΦ. It uses a right triangle to show that these angles are the same and that the triangles are similar.
  • #1
JS-Student
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0
Hi,
This is also a sort of geometry question.
My textbook gives a proof of the relation: sin(θ + Φ) = cosθsinΦ + sinθcosΦ.
It uses a diagram to do so:
upload_2015-10-27_17-22-21.png

http://imgur.com/gLnE2Fn

sin (θ + Φ) = PQ/(OP)
= (PT + RS)/(OP)
= PT/(OP) + RS/(OP)
= PT/(PR) * PR/(OP) + RS/(OR) * OR/(OP)
= cosθsinΦ + sinθcosΦ

My confusion with this is
How do they know that angle TPR also measures θ?
How do they know that triangle TPR is similar to triangle ROQ?


Thanks

The textbook is: Calculus with Analytic Geometry, 2e by George F. Simmons
 
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  • #2
Hey,

I think I kind of figured it out, angle ros = theta, angle ors = 90 -θ

the angle between the TR and the brown line is theta, the angle between PR and the brown line is 90degrees right so angle PRT is 90 - theta and so TPR is theta I've attached a diagram because I feel like these words aren't making sense. Is the diagram clear?

They are similar triangles because they have the same angles.
 

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  • #3
JS-Student said:
Hi,
This is also a sort of geometry question.
My textbook gives a proof of the relation: sin(θ + Φ) = cosθsinΦ + sinθcosΦ.
It uses a diagram to do so:
View attachment 90905
http://imgur.com/gLnE2Fn

sin (θ + Φ) = PQ/(OP)
= (PT + RS)/(OP)
= PT/(OP) + RS/(OP)
= PT/(PR) * PR/(OP) + RS/(OR) * OR/(OP)
= cosθsinΦ + sinθcosΦ

My confusion with this is
How do they know that angle TPR also measures θ?
How do they know that triangle TPR is similar to triangle ROQ?


Thanks

The textbook is: Calculus with Analytic Geometry, 2e by George F. Simmons
They use geometry.

I assume they intend for ∠ORP to be a right angle.

∠RTO measures θ. ∠TRP measures 90° - θ . etc.

(I assume you meant ΔROS, not ΔROQ .)
As for ΔTPR and ΔROS, they're both right triangles each having an acute angle with the same measure, namely θ.
 
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  • #4
thegirl said:
Hey,

I think I kind of figured it out, angle ros = theta, angle ors = 90 -θ

the angle between the TR and the brown line is theta, the angle between PR and the brown line is 90degrees right so angle PRT is 90 - theta and so TPR is theta I've attached a diagram because I feel like these words aren't making sense. Is the diagram clear?

They are similar triangles because they have the same angles.
Oh, wow thanks. It makes sense now. Thanks especially for taking the time to upload a picture.
 

Related to Confused about proof of "sin(θ + Φ) = cosθsinΦ + sinθcosΦ"

1. What is the proof of sin(θ + Φ) = cosθsinΦ + sinθcosΦ?

The proof of this trigonometric identity can be derived using the sum of angles formula for sine: sin(A+B) = sinAcosB + cosAsinB. First, substitute A with θ and B with Φ, giving sin(θ + Φ) = sinθcosΦ + cosθsinΦ. Then, use the commutative property of multiplication to rearrange the terms and obtain sin(θ + Φ) = cosθsinΦ + sinθcosΦ, which is the desired result.

2. Why is it important to understand this proof?

Understanding this proof is important because it helps to deepen your understanding of trigonometric identities and how they relate to one another. It also allows you to confidently use this identity in calculations and problem-solving.

3. Can this proof be used to derive other trigonometric identities?

Yes, this proof can be used to derive other trigonometric identities. For example, by substituting θ with -Φ, we can obtain the identity sin(-Φ) = -sinΦ, which can then be used to prove other identities.

4. Are there any limitations to this proof?

One limitation of this proof is that it only works for the specific case of sin(θ + Φ). It cannot be used to prove identities involving other trigonometric functions, such as cosine or tangent.

5. How can I apply this proof in real-life situations?

This proof can be applied in various real-life situations, such as in physics and engineering calculations involving angles and waves. It can also be used in navigation and surveying to determine distances and angles between objects.

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