Converting 2D density (circle) to 3D density (sphere)

In summary, the problem is converting 2D density to 3D density for a circle and sphere with the same radius and uniform distribution of objects. This is demonstrated through a scenario where crabs and fish forage for plankton in 2D and 3D spaces respectively. The crab has a detection area of ∏*acuity^2 and the fish has a detection volume of (4/3)*∏*acuity^3. The question is whether the number of prey within the 2D detection zone can be converted to the number of prey within the 3D detection zone (or vice versa). However, there are considerations to be made due to the differences in densities between water and land, known as
  • #1
Jimbo2
1
0
Hi All,
I'm looking for help in converting 2D density (objects/area) in a circle to 3D density (objects/volume) in a sphere, the circle and sphere having the same radius and distribution of objects being uniform.

To make this problem more intuitive, here's a sample application: both crabs and fish forage on the same plankton in the water column. The crab can only access plankton as he walks on the ground (i.e., he forages in 2D space), but the fish can access the plankton in the water column (i.e., he forages in 3D space). The crab has a detection area of ∏*acuity^2 while the fish has a detection volume of (4/3)*∏*acuity^3. Given a prey density, can the number of prey within the 2D detection zone be converted to the number of prey within the 3D detection zone (or vice versa)? I may be overthinking this, but help is much appreciated! Thanks!
 
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  • #2
In your concrete example, the crab's feeding zone isn't really 2D - it's a thin sheet. Since the crab's detection range in the vertical direction can taken to extend right through th sheet you can treat it as 2D. But maybe this isn't really the scenario that you want to apply it to.
 
  • #3
In addition to what haruspex mentioned, one thing you should consider is the differences in the situations of depth (like water) and area (like land) with regards to the densities.

For example, the water based situation will have densities that will most likely be a lot sparser and weirdly distributed in land.

It's called the "Curse Of Dimensionality":

http://en.wikipedia.org/wiki/Curse_of_dimensionality
 

Related to Converting 2D density (circle) to 3D density (sphere)

1. How do you calculate the 3D density of a sphere from a given 2D density of a circle?

The formula for calculating the 3D density of a sphere involves multiplying the 2D density of a circle by the height of the sphere. This height can be determined by dividing the volume of the sphere by the area of the circle. The final equation is: 3D density = 2D density * (volume of sphere / area of circle).

2. Can the 2D density and 3D density of a sphere be the same?

No, the 2D density and 3D density of a sphere cannot be the same. This is because the 2D density only takes into account the surface area of the sphere, while the 3D density includes the entire volume of the sphere. Therefore, the 3D density will always be greater than the 2D density.

3. How does the density of a sphere change as its size increases?

The density of a sphere will decrease as its size increases. This is because as the sphere gets larger, its volume increases at a faster rate than its surface area. Therefore, the same amount of mass is spread out over a larger volume, resulting in a lower density.

4. Is the density of a sphere affected by its shape?

Yes, the density of a sphere is affected by its shape. A sphere with a more irregular shape, such as an egg-shaped sphere, will have a slightly different density than a perfectly round sphere. This is because the volume and surface area will be slightly different for each shape.

5. How does the density of a sphere compare to other 3D shapes?

The density of a sphere is generally higher than other 3D shapes with the same volume. This is because a sphere has the smallest surface area compared to other shapes with the same volume. This means that the same amount of mass is concentrated in a smaller space, resulting in a higher density.

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