Converting Newton to Joule: Understanding Energy Transfer in Crankshafts

[Bjarne]

I want to know how Newton can be converted to energy (Joule).
At least approximately...

For example let's say a crankshaft transfer a force, - exactly 100000 Newton

How much energy would be transferred be per second, - included all what is "lost" to heat etc..

 

[Vanadium 50]

You can't convert Newtons to Joules, just like you can't convert meters to seconds. They are different units.

 

[technician]

a Newton is a unit of FORCE.
A joule is a unit of ENERGY
Energy = force x distance moved by the force

 

[malinarn]

not sure if this is obvious or not...but for your example with the crankshaft: if it has a force of 100,000 N and you move it a distance of 2 meters, you have done work. work is equal to energy. That, my friend, is how you relate joules to Newtons.

 

[PJC01]

I can explain the process of converting Newton to Joule and how it relates to energy transfer in crankshafts.

First, it is important to understand that Newton (N) is a unit of force, while Joule (J) is a unit of energy. In order to convert from Newton to Joule, we need to consider the equation F = ma, where F is force, m is mass, and a is acceleration.

In the case of a crankshaft transferring a force of 100000 Newton, we would need to know the mass and acceleration involved in order to calculate the energy transfer. Without this information, it is not possible to provide an exact conversion. However, we can provide an approximate conversion by assuming a standard mass and acceleration for a crankshaft.

Let's say the mass of the crankshaft is 1 kg and the acceleration is 1 m/s^2. Plugging these values into the equation F = ma, we get a force of 1 Newton. This means that 1 Newton is equivalent to 1 kg*m/s^2.

Now, to convert from Newton to Joule, we need to consider the equation W = F*d, where W is work (which is equivalent to energy), F is force, and d is distance. If we assume that the crankshaft rotates 1 full revolution (360 degrees) per second, we can use the formula d = 2πr, where r is the radius of the crankshaft. Assuming a radius of 10 cm (0.1 m), we get a distance of 0.628 m for one full revolution.

Therefore, the energy transferred per second would be 1 Joule (equivalent to 1 Newton) multiplied by 0.628 m, which equals approximately 0.628 Joules per second. This calculation does not take into account any energy loss due to friction or heat, which would require more specific information about the crankshaft and its operation.

In summary, to convert from Newton to Joule, we need to consider the equations F = ma and W = F*d, and we would need more specific information about the crankshaft in order to provide an exact conversion.