- #1
roshan2004
- 140
- 0
I have had no problem while finding the eigen vectors for the x and y components of pauli matrix. However, while solving for the z- component, I got stuck. The eigen values are 1 and -1. While solving for the eigen vector corresponding to the eigen value 1 using [tex](\sigma _z-\lambda I)X=0[/tex],
I got [tex]\left( \begin{matrix} 0 & 0 \\ 0 & -2 \end{matrix} \right)\left( \begin{matrix} x \\ y\end{matrix} \right)=0[/tex]
Now, how can I find the eigen vector for eigen value 1 with this relation since it will give me only [tex]-2y=0[/tex]
I got [tex]\left( \begin{matrix} 0 & 0 \\ 0 & -2 \end{matrix} \right)\left( \begin{matrix} x \\ y\end{matrix} \right)=0[/tex]
Now, how can I find the eigen vector for eigen value 1 with this relation since it will give me only [tex]-2y=0[/tex]