Electromagnetic waves and polarity

In summary: The EM waves generated by both radio antennas and lasers have an e-field vector that oscillates back and forth, from positive to negative, and will cause charges to also oscillate back and forth over time.You get radiation when you have a changing dipole. Your "one direction" produces a changing dipole (although not as strong as the lower plot)But the changing dipole flips polarity in one and not the other. Is that insignificant?There are only so many times I am willing to repeat myself. Saying the same thing that I said before is unlikely to work any better than the last two times.There are only so many times I am willing to repeat myself. Saying the same thing that I said before
  • #1
jaydnul
558
15
Say you have a transmitting whip antenna. If you send a quick DC burst into it, you will get the electrons in the antenna accelerating in one direction like this:
field_a.gif

If that EM wave is then absorbed by a receiving whip antenna, the electrons will also move in one direction. The polarity of the EM wave is only one direction.

Conversely, if we do things normally and send an AC signal into the transmitting antenna, then the electrons will move back and forth which will transmit an EM wave with an alternating polarity.

So am I right in thinking that a standard over the air radio signal is coherent light with 2 different polarities, while something like a laser is coherent light, but only one polarity?
 
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  • #2
Jd0g33 said:
If that EM wave is then absorbed by a receiving whip antenna, the electrons will also move in one direction. The polarity of the EM wave is only one direction.

That's a good question and I'm not sure what the answer is.

Jd0g33 said:
So am I right in thinking that a standard over the air radio signal is coherent light with 2 different polarities, while something like a laser is coherent light, but only one polarity?

The EM waves generated by both radio antennas and lasers have an e-field vector that oscillates back and forth, from positive to negative, and will cause charges to also oscillate back and forth over time.
 
  • #3
You need to better define "quick DC burst".

If the antenna develops a net charge, that charge had to come from somewhere, so now there is a region of opposite charge. You've created a dipole, and the receiving antenna will see a bipolar signal.
 
  • #4
Say I have this setup:
6ebNCa.png

...and the DC source is increasing at a rate of 1 V/sec. The electrons are being accelerated in one direction and will emit EM radiation.

Now say I have this setup:
YsbnYm.png

...and the AC source is at 1 Vpp, 1/4 hz. The electrons are being accelerated in both directions and will emit EM radiation.

Assume there is some resistance so the current isn't infinite. If I put a receiving antenna in front of both these transmitters, would I get the exact same signal? The difference being the AC transmitter is accelerating it's electrons at 1 V/sec in the opposite direction of the DC transmitter for half the time.
 
  • #5
You get radiation when you have a changing dipole. Your "one direction" produces a changing dipole (although not as strong as the lower plot)
 
  • #6
But the changing dipole flips polarity in one and not the other. Is that insignificant?
 
  • #7
There are only so many times I am willing to repeat myself. Saying the same thing that I said before is unlikely to work any better than the last two times.
 
  • #8
Vanadium 50 said:
There are only so many times I am willing to repeat myself. Saying the same thing that I said before is unlikely to work any better than the last two times.

"You get radiation when you have a changing dipole." Great, but I'm still confused.

The EM wave's frequency is directly related to the frequency of the AC signal, but how is the frequency of the DC case determined when it emits its radiation?
 
  • #9
Jd0g33 said:
proxy.php?image=https%3A%2F%2Fimagizer.imageshack.us%2Fv2%2F514x272q90%2F923%2F6ebNCa.png

...and the DC source is increasing at a rate of 1 V/sec. The electrons are being accelerated in one direction and will emit EM radiation.

With that definition, it isn't a steady DC source any longer, as you change the voltage the current will also change through the load

Once the applied voltage stops changing, then it will reach equilibrium and will be steady ... no emitted EM

Jd0g33 said:
The EM wave's frequency is directly related to the frequency of the AC signal, but how is the frequency of the DC case determined when it emits its radiation?

it doesn't have a frequency, as there is no oscillation as with an AC voltage, it's just a momentary pulse

eg ... lightning discharge, spark gap transmitter
because it doesn't have a defined freq, it is very broadband and is heard well across the radio spectrumDave
 
  • #10
davenn said:
it doesn't have a frequency, as there is no oscillation as with an AC voltage, it's just a momentary pulse

eg ... lightning discharge, spark gap transmitter
because it doesn't have a defined freq, it is very broadband and is heard well across the radio spectrumDave

So really it's just emitting incoherent photons at a range of different frequencies? But doesn't the photon frequency depend on the rate of acceleration of the charge? So if all the electrons were under the same acceleration, wouldn't they be emitting the same frequency?
 

1. What are electromagnetic waves?

Electromagnetic waves are a type of energy that is produced by the movement of electrically charged particles. They consist of an electric field and a magnetic field that are perpendicular to each other, and travel through space at the speed of light.

2. How are electromagnetic waves created?

Electromagnetic waves are created when an electrically charged particle, such as an electron, accelerates or changes direction. This movement creates a disturbance in the electric and magnetic fields, which then propagate as a wave through space.

3. What is the relationship between frequency and wavelength in electromagnetic waves?

The frequency and wavelength of an electromagnetic wave are inversely proportional to each other. This means that as the frequency increases, the wavelength decreases, and vice versa. This relationship is described by the equation c = λν, where c is the speed of light, λ is the wavelength, and ν is the frequency.

4. What is polarity in electromagnetic waves?

Polarity refers to the direction of the electric and magnetic fields in an electromagnetic wave. In a transverse wave, such as an electromagnetic wave, the electric and magnetic fields are perpendicular to the direction of propagation. The direction of the electric field is considered the polarity of the wave.

5. How are electromagnetic waves used in everyday life?

Electromagnetic waves have a wide range of everyday applications, including radio and television communication, cell phones, microwave ovens, and medical imaging technologies like X-rays and MRI machines. They are also used in industries such as transportation, manufacturing, and energy production.

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