- #1
michii15
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- TL;DR Summary
- Find the only periodic solution for π¦β²+π¦=π(π₯) with π:βββ has a period of 2π and is 1 for π₯(0,π) and β1 for π₯(βπ,0).
Find the only periodic solution for π¦β²+π¦=π(π₯) with π:βββ has a period of 2π and is 1 for π₯(0,π) and β1 for π₯(βπ,0).
The ODE is easy to solve: π¦(π₯)=exp(βπ₯)β π+1 and π¦(π₯)=exp(βπ₯)β πβ1. But how can I find the π such that the solution is periodic with a period of 2π?
The solution is: https://i.stack.imgur.com/S21Ze.png
Thanks for your help.
The ODE is easy to solve: π¦(π₯)=exp(βπ₯)β π+1 and π¦(π₯)=exp(βπ₯)β πβ1. But how can I find the π such that the solution is periodic with a period of 2π?
The solution is: https://i.stack.imgur.com/S21Ze.png
Thanks for your help.