MHB Finding Least Value m with Property P in Discrete Math

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The problem involves determining the least value m such that any family F of distinct subsets of a set X with n elements, where |F| > m, possesses property P. Property P is defined by the existence of subsets A and B in F, where A is a proper subset of B and the difference |B\A| equals 1. The solution indicates that m equals 2^(n-1), supported by two main points: a specific collection of subsets with size 2^(n-1) that does not satisfy property P and the implication that any larger collection must contain subsets that fulfill the property. This conclusion can be demonstrated through induction and the concept of binary representation in subsets. The discussion ultimately confirms the solution to the problem.
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Consider a set X with |X|=n≥1 elements. A family F of distinct subsets of X is sad to have property P if there exist A and B in F, such that A is a proper subset of B and |B\A|=1. Determine the least value m, so that any F with |F|>m has property P.
This is a problem asked by our Discrete mathematics teacher,but i have no idea where to start from.. If anybody could help me?
 
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There have been no replies, but the question is solved?

Anyway, the answer is $2^{n-1}$. Here are substantial hints to prove this:

1. There is a collection $\mathcal{F}$ of subsets with |$\mathcal{F}|=2^{n-1}$ that does not satisfy P. One way to prove this is by induction on n.

2. If $\mathcal{F}>2^{n-1}$, $\mathcal{F}$ satisfies P. Think of the subsets as being represented by the binary numbers (bit strings of length n). In a subset of a Gray code with more than $2^{n-1}$ elements, show that the subset contains 2 consecutive elements.
 
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