Why Is the Cross Sectional Area of a Coil Used in Calculating Flux Linkage?

In summary, the flux through a coil is given by the BANcos(theta) equation with B being the flux density, N being the number of turns in the coil, and A being the cross sectional area of the coil.
  • #1
JSmith85
3
0
Flux linkage in a wire coil is given by BANcos(theta) with B being flux density, N being the number of turns in a coil and A being the cross sectional area of the coil and theta being the angle between the normal to the plane of the coil and the magnetic field.

Is anybody able to explain why it is the cross sectional area of the coil?

I understand it in terms of a length of wire as the cross section of that is cutting field lines but in terms of a coil I'm confused as you have the whole central area of the coil which is empty and therefore not cutting field lines so why is the cross sectional area of the coil used and not just the area of the coil cutting the field lines?
 
Physics news on Phys.org
  • #2
It's simply because voltage induced in a coil is not depending on "wires cutting field lines". It depends on the (various) flux, that the wire surrounds:

Say you have some square shaped winding ( 1m x 1m ) in a magnetic field. Now you somehow expand the winding to 2m x 2m. Of course the wires must cross the magnetic field due to this expansion, but that doesn't matter. It's the expansion of the cross section area ( 1m2 → 4m2 ) that matters. The winding surrounds more flux by the expansion.

Emf = dΨn/dt , Ψn = Ψ*N , Ψ = B * A (flux)
 
  • #3
Hesch said:
It's simply because voltage induced in a coil is not depending on "wires cutting field lines". It depends on the (various) flux, that the wire surrounds:

Say you have some square shaped winding ( 1m x 1m ) in a magnetic field. Now you somehow expand the winding to 2m x 2m. Of course the wires must cross the magnetic field due to this expansion, but that doesn't matter. It's the expansion of the cross section area ( 1m2 → 4m2 ) that matters. The winding surrounds more flux by the expansion.

Emf = dΨn/dt , Ψn = Ψ*N , Ψ = B * A (flux)

Ok I think you have lost me a little bit now. So how does this fit with the idea of flux through a single wire.
 
  • #4
JSmith85 said:
how does this fit with the idea of flux through a single wire.
I'm not sure, what you mean by the question.
Say you have a straight piece of wire, you hold it horizontal while you are running over the North-pole, thereby inducing emf between the ends of the wire.

Now you want to measure this voltage, so you have a volt-meter and connect its probes to the ends of the wire. Maybe you could tape the leads of the volt-meter to the wire, so they are fixed. Then you start running again, and you will measure nothing, because a counter-emf is induced in the leads of your voltmeter as you are running.

You cannot measure/sense an emf, without forming a closed loop including your volt-meter. Currents can only flow through closed circuits.

That's why areas surrounded by a wire ( not the wire itself ) are regarded by calculations of an emf in a coil.

Having a varying magnetic field through a wire will only induce a circulation emf (closed loop) inside the wire, resulting in Eddy-currents in the wire.
 
  • #5
Hesch said:
I'm not sure, what you mean by the question.
Say you have a straight piece of wire, you hold it horizontal while you are running over the North-pole, thereby inducing emf between the ends of the wire.

Now you want to measure this voltage, so you have a volt-meter and connect its probes to the ends of the wire. Maybe you could tape the leads of the volt-meter to the wire, so they are fixed. Then you start running again, and you will measure nothing, because a counter-emf is induced in the leads of your voltmeter as you are running.

You cannot measure/sense an emf, without forming a closed loop including your volt-meter. Currents can only flow through closed circuits.

That's why areas surrounded by a wire ( not the wire itself ) are regarded by calculations of an emf in a coil.

Having a varying magnetic field through a wire will only induce a circulation emf (closed loop) inside the wire, resulting in Eddy-currents in the wire.

Sorry I think you have misunderstood I'm not talking about the emf just the magnetic flux.

Let me try again if I have a single wire in a magnetic field of a known cross sectional area flux is given by BA with A being the cross sectional area of the wire however if i have a coil ( for arguments sake let us pretend it is square with each side being made up by identical wires to the first example) then A becomes the cross sectional area of the coil rather than the sum of the cross sectional areas of the wires making it up, why is this?
 
  • #6
JSmith85 said:
Flux linkage in a wire coil is given by BANcos(theta)
B*A*N*cos(θ) is an expression that equals Ψn ( the flux linkage ). A is the area surrounded by the wire: the area within the winding.
The emf in the winding = dΨn/dt.
This emf is used to calculate transformers ( E = 4.44 * f * N * A * B , sinusoidal voltage ), motors, mutual induction, self-induction, etc.
You could define A being the area of the wire itself, but then you are calculating something else ( Eddy voltage ).
I have understood that you find it strangely that flux in "thin air" induces voltage in a wire, but so it is. That's a phenomenon made by the nature.
Using A = Awire, you can calculate Eddy-currents within the wire, because now you are regarding a closed loop here.

So you must consider what you want to calculate by these flux linkages: Eddy-losses or mutual/self inductions?
Regarding only flux linkages as a "stand alone" ( no emf, no current ) doesn't make much sense: Who cares about a flux linkage if it has connection with nothing?
 

1. What is flux linkage in a wire coil?

Flux linkage refers to the amount of magnetic flux that passes through a wire coil. It is a measure of the strength of the magnetic field generated by the coil.

2. How is flux linkage measured?

Flux linkage is typically measured in units of weber-turns (Wb-t), which is the product of the magnetic flux (measured in webers) and the number of turns in the coil.

3. What factors affect flux linkage in a wire coil?

The amount of flux linkage in a wire coil is influenced by several factors, including the number of turns in the coil, the strength of the magnetic field, and the area of the coil.

4. Why is flux linkage important?

Flux linkage is an important concept in electromagnetism because it helps us understand how a changing magnetic field can induce an electric current in a wire coil. This phenomenon is known as electromagnetic induction and is the basis for many electrical devices.

5. How can flux linkage be increased in a wire coil?

The amount of flux linkage in a wire coil can be increased by increasing the number of turns in the coil, increasing the strength of the magnetic field, or increasing the area of the coil. Additionally, using a ferromagnetic core inside the coil can also increase the flux linkage.

Similar threads

Replies
1
Views
370
  • Electromagnetism
2
Replies
43
Views
1K
  • Electromagnetism
Replies
16
Views
1K
  • Electromagnetism
Replies
7
Views
2K
Replies
19
Views
3K
Replies
13
Views
2K
  • Electromagnetism
6
Replies
191
Views
14K
  • Electromagnetism
Replies
3
Views
3K
  • Electromagnetism
Replies
1
Views
1K
  • Electromagnetism
Replies
3
Views
2K
Back
Top