Function Problem: Area of Rectangle with 100ft Perimeter

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To express the area of a rectangle with a perimeter of 100 feet as a function of the length L, the perimeter equation 100 = 2w + 2l can be rearranged to find width in terms of length. The correct area function is A(w) = w(50 - w), which simplifies to A = -w^2 + 50w. However, since the problem requires the area as a function of length, width must be expressed in terms of length using the perimeter equation. Substituting this into the area formula yields a function for area based on length.
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Homework Statement



Express the area of a rectangle with the perimeter of 100 feet as a function of the lengh L of one of its sides


Homework Equations


100=2w+2l


The Attempt at a Solution


As far as I can get is,

L = 50 -2w

Just writing the function is a problem, I assume it's something like but I'm not sure, sorry if I'm completely off it's been a long day.
A(W) = (50-2w)(w) = 50w - 2w^2
or
A = w(50-w)
 
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You successfully wrote the function for area (in two equivalent forms).
 
If 100=2L+2W

then L=50-W but L\neq 50-2W

Therefore your 2nd equation for the function is the correct one. A=-W^2+50W

But the question asked as a function of the length, not width. It will be similar though. Just make width the subject of the perimeter equation and substitute into the area formula.
 
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