- #1
PFuser1232
- 479
- 20
"If ##f## is continuous on ##[a,b]## and:
$$g(x) = \int_a^x f(t) dt$$
Then ##g## is continuous on ##[a,b]##, differentiable on ##(a,b)##, and ##g'(x) = f(x)##."
This is the first fundamental theorem of calculus. I'm curious as to why ##g## is only differentiable on ##(a,b)##, but not ##[a,b]##.
$$g(x) = \int_a^x f(t) dt$$
Then ##g## is continuous on ##[a,b]##, differentiable on ##(a,b)##, and ##g'(x) = f(x)##."
This is the first fundamental theorem of calculus. I'm curious as to why ##g## is only differentiable on ##(a,b)##, but not ##[a,b]##.