Gravity is std. therefore can we rate a 'mass at height' by watts?

In summary, wind turbines are primarily listed by their wattage (1.5MW etc.), with the rating being a guide for a given mass at a given height. However, for a given mass, at a given height; due to standard gravity, can we state that this mass, on falling can deliver a maximum amount of watts of power? Eg. for 1.5MW, the power output is 5.45KW for a period of 18s.
  • #1
marcophys
152
20
For example... wind turbines are primarily listed by their wattage (1.5MW etc.)
Presumably their output is varied according to rotational speed, so I'm guessing that the rating is simply a guide.

However, for a given mass, at a given height; due to standard gravity, can we state that this mass, on falling can deliver a maximum amount of watts of power.

Eg.
Work = force times distance.
Power = work divided by time.

Work = 100kg @ 100m = 98,000 joules
Time = 100m freefall = 4.5s
Power = 21.8KW

But that is freefall, and nothing is being driven.
If a chain and gearbox, was attached to the mass, that then rotated a generator... the rate of descent would be very slow.
Leaving aside friction... work must be done to turn the generator?

How then do we predict the output of the generator?

Eg. the mass takes 4 times as long to travel 100m
Is the power output 21.8KW/4 = 5.45KW for a period of 18s ?

Or, to put this into a 1KW element fire: we could only get 98s of use, from 100kg @ 100m.

Surprisingly little, if the above is true.
But is it true?

Is 21.8KW the maximum we can get out of 100kg @ 100m?
 
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  • #2
marcophys said:
Eg. the mass takes 4 times as long to travel 100m
Is the power output 21.8KW/4 = 5.45KW for a period of 18s ?
yes. The total energy released from 100 kg lowered 100 meters in the Earth's surface gravity is 9.8x104 joules. You can release it over a longer time to get fewer watts (joules per second), but that's like making a glass of water last longer by drinking it more slowly; it takes longer but you don't end up with any more water than if you had gulped it at once.

Is 21.8KW the maximum we can get out of 100kg @ 100m?
No. You could, for example, let the weight fall freely (just pulling the rope behind it) for 99 meters, and then apply the load, bringing the weight to rest just as it touches the ground. You'd get your 9.8x104 joules in about .04 seconds, a short burst of very high power output.

21.8 kw is the (unreachable) upper limit on the average power over the entire time that the weight is falling.
 
  • #3
Nugatory said:
yes. The total energy released from 100 kg lowered 100 meters in the Earth's surface gravity is 9.8x104 joules. You can release it over a longer time to get fewer watts (joules per second), but that's like making a glass of water last longer by drinking it more slowly; it takes longer but you don't end up with any more water than if you had gulped it at once.


No. You could, for example, let the weight fall freely (just pulling the rope behind it) for 99 meters, and then apply the load, bringing the weight to rest just as it touches the ground. You'd get your 9.8x104 joules in about .04 seconds, a short burst of very high power output.

21.8 kw is the (unreachable) upper limit on the average power over the entire time that the weight is falling.

I really like that! :wink:

It got me thinking that a given amount of GPE can be attained by different combinations of height and mass. Each combination of m and h implies a different maximum rate of [edit: energy] transfer - the highest (mean) power being obtained with the biggest possible mass and the smallest height - because that involves the shortest possible descent time. There's a analogous electrical model with Energy stored in a capacitor. The maximum power obtainable is limited by the Inductance of the circuit.
 
Last edited:
  • #4
Thanks Nugatory for that solid response :smile:

I had not considered the 'freefall to point of impact'.
This fact therefore eliminates the possibility of rating a 'mass at height' by watts.
Clearly it can only be rated by joules (as a single universal number).

I must confess to feeling glad to have asked this question in this format.

The image conjured, of a mass falling in a straight line, allows for so many 'easy to calculate scenarios', with the result being that 'power' as a concept, becomes much more accessible.

I was thinking about your suggestion of power production over a period of 0.04s
power = 2,450KW

and then relating it to:
sophiecentaur said:
the biggest possible mass and the smallest height

It's really good.
I'm really happy :biggrin:
 
  • #5


I can understand your curiosity about the relationship between gravity, mass, and power output. However, it is not accurate to say that gravity is "standard" or "constant" in all situations. Gravity varies depending on the location and the mass of the objects involved. In addition, power output is not solely determined by the mass and height of an object, but also by other factors such as the efficiency of the systems involved.

Wind turbines are rated by their wattage because it is a measure of the power they can produce under optimal conditions. This includes the wind speed, the design of the turbine, and the efficiency of the generator. The rotational speed of the turbine blades is also a factor in determining the power output.

In the example you provided, the power output is only calculated for the freefall scenario and does not take into account the work required to turn the generator. In reality, there would be losses due to friction and other factors that would affect the power output. It is not accurate to assume that the power output would be the same for a longer period of time or with a chain and gearbox attached.

To accurately predict the power output of a generator, a more detailed analysis of the system would be required, taking into account all the factors involved. It is not as simple as just multiplying the mass and height. Therefore, it is not accurate to say that 100kg @ 100m can only produce a maximum of 21.8KW.

In conclusion, while there may be a relationship between gravity, mass, and power output, it is not a straightforward one and cannot be accurately predicted without considering all the factors involved in a specific system.
 

1. What is the significance of gravity being a standard?

The fact that gravity is a standard means that it is a fundamental force of nature that is consistent and predictable. This allows us to make accurate calculations and predictions about the behavior of objects in the presence of gravity.

2. How does gravity affect an object's mass at different heights?

Gravity affects an object's mass at different heights by pulling it towards the center of the Earth. This results in a change in weight, as the gravitational force is directly proportional to an object's mass.

3. Can we measure a mass at height using watts?

No, watts are a unit of power, not mass. Mass is typically measured in units such as kilograms or pounds, while watts are used to measure the rate of energy transfer or work done.

4. How does the rate of energy transfer or work done relate to gravity and mass at height?

The rate of energy transfer or work done is related to gravity and mass at height through the formula W = mgh, where W represents work, m represents mass, g represents the acceleration due to gravity, and h represents the height of the object.

5. Are there any factors that can affect the accuracy of measuring mass at height using watts?

Yes, there are several factors that can affect the accuracy of measuring mass at height using watts. These include variations in the strength of gravity at different locations, air resistance, and errors in measurement. It is important to consider these factors and make adjustments to ensure accurate results.

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